A-LEVEL的数学题Theequationofacurveisy=6/(5-2x)(i)Calculatethegradientofthecurveatthepointwherex=1.(ii)Apointwithcoordinates(x,y)movesalongthecurveinsuchawaythattherateofincreaseofyhasaconstantvalueof

Question

A-LEVEL的数学题
The equation of a curve is y =6/(5 - 2x)
(i) Calculate the gradient of the curve at the point where x=1.
(ii) A point with coordinates (x,y) moves along the curve in such a way that the rate of increase of
y has a constant value of 0.02 units per second.Find the rate of increase of x when x = 1.
(iii) The region between the curve,the x-axis and the lines x = 0 and x = 1 is rotated through 360?
about the x-axis.Show that the volume obtained is12π
第三小问,
我不是要翻译.....
第三问旋转怎么会是about?

Answer 1

一条曲线的方程y =6/(5 - 2x )
(i)计算在点的曲线的坡度x=1.
( ii ) A点沿着曲线按照增加的率y每秒有0.02个单元的一种经常的价值的这样一种方式协调( x,y )行动.找到增加的率x当时x = 1.
( iii )曲线,x路线和线x之间的该地区= 0和x = 1被旋转穿过360?
关于x路线……