若a0=b0=1,an=an-1+2bn-1,bn=an-1+bn-1(n∈N*),则a2005^2-b2005^2=?a2005^2=a2005的平方

Question

若a0=b0=1,an=an-1+2bn-1,bn=an-1+bn-1(n∈N*),则a2005^2-b2005^2=?
a2005^2=a2005的平方

Answer 1

#include
void main()
{
long a0=1;
long b0=1;
int i;
long m;
long n;
double s;
for(i=0;i