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(a^4/3-8a^1/3b)/(4b^2/3+2三次根号ab+a^2/3)/(1-2三次根号b/a)*三次根号a
题目详情
(a^4/3-8a^1/3b)/(4b^2/3+2三次根号ab+a^2/3)/(1-2三次根号b/a)*三次根号a
▼优质解答
答案和解析
(a^4/3-8³√ab)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a
=³√a(a-8b)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a
=³√a(³√a-2³√b)(a^2/3+2³√ab+4b^2/3)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a
=³√a(³√a-2³√b)/(³√a-2³√b)
=³√a
=³√a(a-8b)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a
=³√a(³√a-2³√b)(a^2/3+2³√ab+4b^2/3)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a
=³√a(³√a-2³√b)/(³√a-2³√b)
=³√a
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