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已知COS(四分之派+而发)=五分之三而发大于等于二分指派小于等于二分之三派求1-COS2而发+SIN2而发/1-TAN而发而发就是аcos(π/4+α)=3/5π/2≤α〈3π/21-cos2α+(sin2α)/(1-tanα)
题目详情
已知COS(四分之派+而发)=五分之三 而发大于等于二分指派小于等于二分之三派 求1-COS2而发+SIN2而发/1-TAN而发
而发就是а
cos(π/4+α)=3/5 π/2≤α〈3π/2
1-cos2α+(sin2α)/(1-tanα)
而发就是а
cos(π/4+α)=3/5 π/2≤α〈3π/2
1-cos2α+(sin2α)/(1-tanα)
▼优质解答
答案和解析
cos(π/4+α)=3/5 π/2≤α〈3π/2
sin(π/4+α)=-4/5 π/2≤α〈3π/2
tan(π/4+α)=-4/3
(1+tanα)/(1-tanα)=-4/3
tana=7
sin(π/2+2α)=-24/25
cos2α=24/25
cos(π/2+2α)=-7/25
sin2α=-7/25
1-cos2α+(sin2α)/(1-tanα)
=1-24/25-7/25/(1-7)=13/150
sin(π/4+α)=-4/5 π/2≤α〈3π/2
tan(π/4+α)=-4/3
(1+tanα)/(1-tanα)=-4/3
tana=7
sin(π/2+2α)=-24/25
cos2α=24/25
cos(π/2+2α)=-7/25
sin2α=-7/25
1-cos2α+(sin2α)/(1-tanα)
=1-24/25-7/25/(1-7)=13/150
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