早教吧作业答案频道 -->其他-->
英语翻译LiYundi,awell-knownChinesepianist,alwayslovedmusic.Hewasbornin1982inChongqing.Whenhewasasmallboy,hecouldhumsongsanddifficultpiecesofmusic.hebegantolearntheaccordionattheageoffour,andhestartedtolearnt
题目详情
英语翻译
Li Yundi,a well-known Chinese pianist,always loved music.He was born in 1982 in Chongqing.When he was a small boy,he could hum songs and difficult pieces of music.hebegan to learn the accordion at the age of four,and he started to learn the piano when he was seven.In October 2000,Li Yundi took part in the 14th Chopin International Piano Competition in Poland.He won first prize in his group.
Li Yundi,a well-known Chinese pianist,always loved music.He was born in 1982 in Chongqing.When he was a small boy,he could hum songs and difficult pieces of music.hebegan to learn the accordion at the age of four,and he started to learn the piano when he was seven.In October 2000,Li Yundi took part in the 14th Chopin International Piano Competition in Poland.He won first prize in his group.
▼优质解答
答案和解析
著名的中国钢琴家,李云迪,一直喜爱音乐.他于1982年出生在重庆.当他还是一个小男孩子的时候,他就能哼唱歌曲和有难度的乐曲.在他四岁时,开始学习手风琴,在七岁时他开始学习钢琴.2000年10月,李云迪参加了在波兰举办的第十四届肖邦国际钢琴大赛.他赢得了他所在小组的一等奖.他也是在大奖赛70年历史中第一位获此奖的中国钢琴家.
看了 英语翻译LiYundi,aw...的网友还看了以下:
已知x,y,z满足y+z/x=z+x/y=x+y/z=k,求k的值我只知道一个,∵y+z/x=z+ 2020-04-26 …
已知x^y=y^x,求y的导数。令F[x,y(x)]=x^y-y^x=o有两种方法,一种是求复合函 2020-05-14 …
先化简,再求值 (1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=20 2020-05-16 …
x+y=(x+y)*1=(x+y)*(1/x+9/y)=1+9+y/x+9x/y=10+y/x+9 2020-05-20 …
英语翻译LiYundi,awell-knownChinesepianist,alwaysloved 2020-06-17 …
①y=x,x=1,y=0②y=根号x,x=4,y=0绕x轴旋转产生的旋转体的体积;③y=x^2,y 2020-06-25 …
把下列各式分解因式:(x+y)^2-(x+y)^3要写过程哦1:(x+y)^2-(x+y)^3=2 2020-06-27 …
解方程组1x*x+y*y=10x+xy+y=72x+y+xy=7x*x+y*y+xy=133(x+ 2020-07-17 …
把下列各式化成(x-y)的n次方(x-y)³×(y-x)²×(x-y)(x-y)×(x-y)的4次 2020-07-18 …
初二英语语法LiYundi,awell-knowChinesepianist,alwaysloved 2021-01-31 …