设y=e2log10x+x-tanx，则y′=（）A.e2xln10+12x-sec2xB.e2xln10+12x-sec2xC.e2xln10+12x-secx•tanxD.e2x•ln10+12x-11+x2

Question

设y=e²log₁₀x+

√(x)-tanx，则y′=（　　）

A.

(e2)/(x)ln10+(1)/(2√(x))-sec²x

B.

(e2)/(xln10)+(1)/(2√(x))-sec²x

C.

(e2)/(x)ln10+(1)/(2√(x))-secx•tanx

D.

(e2)/(x•ln10)+(1)/(2√(x))-(1)/(1+x2)

Answer 1

由题意，y′=(e2log10x)′+(√(x))-(tanx)′
=e2•(1)/(xln10)+(1)/(2√(x))-sec2x
故选：B