解方程和算式X^2+X+1/(X^2+X)=2还有算式:根号1.5*根号(8/3)+(根号2-2)^-1－(-1/3)^0X^2/(X+2Y)-X+2Y-2x^2+x-1=0怎么得到x=[-1+/-根号5]/2

Question

解方程和算式
X^2+X+1/(X^2+X)=2
还有算式:
根号1.5*根号(8/3)+(根号2-2)^-1－(-1/3)^0
X^2/(X+2Y)-X+2Y-2
x^2+x-1=0怎么得到x=[-1+/-根号5]/2

Answer 1

X^2+X+1/(X^2+X)=2
令x^2+x=a
a+1/a=2
a^2-2a+1=0
a=1
x^2+x-1=0
x=[-1+/-根号5]/2
根号1.5*根号(8/3)+(根号2-2)^-1－(-1/3)^0
=根号(3/2)根号(8/3)+(2+根号2)/(-2)-1
=2-1-根号2/2-1
=-根号2/2
X^2/(X+2Y)-X+2Y-2
=(我还不懂,你教我)