早教吧作业答案频道 -->数学-->
因式分解:(1)(y2+3y)-(2y+6)2(2)4xy2-4x2y-y2.
题目详情
22
222
▼优质解答
答案和解析
(1)(y22+3y)-(2y+6)22
=y22+3y-(4y22+36+24y)
=-3y22-21y-36
=-3(y22+7y+12)
=-3(y+3)(y+4);
(2)4xy22-4x22y-y22=-y(-4xy+4x22+y).
=y22+3y-(4y22+36+24y)
=-3y22-21y-36
=-3(y22+7y+12)
=-3(y+3)(y+4);
(2)4xy22-4x22y-y22=-y(-4xy+4x22+y).
看了 因式分解:(1)(y2+3y...的网友还看了以下:
初三方程组.关于x,y方程组大括号:x^2+y^2=1/2y=x+n有一个实数解,反比例函数y=(- 2020-03-30 …
已知两个圆:C1-X^2+Y^2+4X+Y+1=0C2-x^2+Y^2+2X+2Y+1=0它们的公 2020-05-20 …
解下列不等式组y-4≤3(y-2)1+2y>3(y-1) 2020-06-02 …
数学:已知x≥1,y≥1,求证:x^2y^2-x^2y-xy^2+y-1≥0!已知x≥1,y≥1, 2020-06-06 …
例求过两圆C1:X^2+Y^2-4X+2Y=0和圆C2:X^2+Y^2-2Y-4=0的交点,且圆心 2020-07-09 …
1,(x^2)-2x-9(y^2)+6y2,(x^2)-(y^2)-1-2y 2020-07-30 …
用代入法接下列方程1)y+2=1-x2)x+3y=43)3y-2x=13x+2y=-31/4x+1 2020-08-01 …
(1)3a^2y-3ay+6y(2)-x^2+xy-xz(3)-3ma^3+6ma^2-12ma(4 2020-11-01 …
再将多项式2y^3-y^2+k写成整式的积的形式解法1:设2y^3-y^2+k=(2y+1)(y^2 2020-12-25 …
求函数y=(2-sinx)/(2-cosx)的值域别用这种方法做.→y=(2-sinx)/(2-co 2021-01-31 …