早教吧作业答案频道 -->数学-->
四元一次方程解法.俺赶时间,加上不会matlab,帮帮.0.005083-0.2985a-0.00025b+0.0725c+0.0875d=00.009083+0.00025a+0.306b+0.2025c-0.14d=00.064167+0.0725a-0.2025b-0.10575c-0.0225d=00.006667+0.0875a+0.14b-0.0225c+0.23325d=0
题目详情
四元一次方程解法.俺赶时间,加上不会matlab,帮帮.
0.005083-0.2985a-0.00025b+0.0725c+0.0875d=0
0.009083+0.00025a+0.306b+0.2025c-0.14d=0
0.064167+0.0725a-0.2025b-0.10575c-0.0225d=0
0.006667+0.0875a+0.14b-0.0225c+0.23325d=0
0.005083-0.2985a-0.00025b+0.0725c+0.0875d=0
0.009083+0.00025a+0.306b+0.2025c-0.14d=0
0.064167+0.0725a-0.2025b-0.10575c-0.0225d=0
0.006667+0.0875a+0.14b-0.0225c+0.23325d=0
▼优质解答
答案和解析
syms a b c d
[a,b,c,d]=solve('0.005083-0.2985*a-0.00025*b+0.0725*c+0.0875*d=0','0.009083+0.00025*a+0.306*b+0.2025*c-0.14*d=0',...
'0.064167+0.0725*a-0.2025*b-0.10575*c-0.0225*d=0','0.006667+0.0875*a+0.14*b-0.0225*c+0.23325*d=0')
a = -1.264915611178603343104260187311
b =2.0229725158204830541709095591987
c =-3.8908749382444142140830410100597
d =-1.1436129575444336757949538890652
[a,b,c,d]=solve('0.005083-0.2985*a-0.00025*b+0.0725*c+0.0875*d=0','0.009083+0.00025*a+0.306*b+0.2025*c-0.14*d=0',...
'0.064167+0.0725*a-0.2025*b-0.10575*c-0.0225*d=0','0.006667+0.0875*a+0.14*b-0.0225*c+0.23325*d=0')
a = -1.264915611178603343104260187311
b =2.0229725158204830541709095591987
c =-3.8908749382444142140830410100597
d =-1.1436129575444336757949538890652
 看了 四元一次方程解法.俺赶时间,...的网友还看了以下:
6.设A与B互为对立事件,且P(A)>0,P(B)>0,则下列各式中错误的是( )A. p(a补| 2020-05-16 …
1.一个负数整数a与其倒数1/a,相反数-a相比较,正确的是()A.1/a>-a B.1/a<-a 2020-05-16 …
函数f(x)=ax^2+bx+c(a不等于0),f(x)的导函数是f'(x),集合A={x|f(x 2020-05-16 …
若(a+b)(a-1)>0,则必有()(A)b与a同号(B)a+b与a-1同号(C)a>1(D)b 2020-05-24 …
已知a+b+c>0,ab+bc+ac>0,abc>0,用反证法求证a>0,b>0,c>0的假设为( 2020-06-05 …
已知a,b是有理数,若a在数轴上的对应点的位置如图所示,a+b<0,有以下结论:①b<0;②b-a 2020-07-22 …
已知a+b+c>0,ab+bc+ac>0,abc>0,用反证法求证a>0,b>0,c>0的假设为( 2020-08-01 …
1.若关于x的方程ax²+2(a-b)x+(b-a)=0(a≠0)有两个相等的实数根,则a:b等于 2020-08-02 …
1、写出“a+b〉0”的一个必要非充分条件2、在①a(a-b)≤0,②a>0且b>a,③a(b-a) 2020-12-07 …
概率论问题(急)已知A,B互不相容,且P(A)=0.5,P(B)=0.3,P(B|A)=P(A)=0 2020-12-13 …