早教吧作业答案频道 -->数学-->
(a^2b^2)*(ab^2)*2(ab^2)^2*a^33^100*(-1/3)^101
题目详情
(a^2b^2)*(ab^2)*2(ab^2)^2*a^3 3^100*(-1/3)^101
▼优质解答
答案和解析
(a^2b^2)*(ab^2)*2(ab^2)^2*a^3
=(a^2b^2)*(ab^2)*2(a^2b^4)*a^3
=2a^2b^2*ab^2*a^2b^4*a^3
=2a^(2+1+2+3)b^(2+2+4)
=2a^8b^8
3^100*(-1/3)^101
=3^100*(-1/3)^100*(-1/3)
=[3*(-1/3)]^100*(-1/3)
=(-1)^100*(-1/3)
=1*(-1/3)
=-1/3
=(a^2b^2)*(ab^2)*2(a^2b^4)*a^3
=2a^2b^2*ab^2*a^2b^4*a^3
=2a^(2+1+2+3)b^(2+2+4)
=2a^8b^8
3^100*(-1/3)^101
=3^100*(-1/3)^100*(-1/3)
=[3*(-1/3)]^100*(-1/3)
=(-1)^100*(-1/3)
=1*(-1/3)
=-1/3
看了 (a^2b^2)*(ab^2...的网友还看了以下:
3×2^101+(-2^103)是2的103不是-2的3×2^101+(-2^103)是2的103不 2020-03-30 …
2^2-1^2=2*1+13^2-2^2=2*2+14^2-3^2=2*3+1……(n+1)^2- 2020-05-19 …
已知三角形的三个顶点分别为A(6,-7),B(-2,3),C(2,1),求AC边上的中线所在的直线 2020-06-03 …
用乘法分配律算(2+1.33+2.9)×(1.33+2.9+3.14)-(2+1.33+2.9+3 2020-07-15 …
计算:(1+7/33)+(2+7/33*2)+(3+7/33*3)+...+(10+7/33*10 2020-07-17 …
根式计算化简1、(1/x^2-3x+2)+(1/x^2-x)+(1/x^2+x)+(1/x^2+3 2020-07-30 …
5x^2+16x+12=12x^2-29x+15=12x^2-25xy+12y^2=20a^2+42 2020-10-31 …
求助分解因式(1)t^2-2t-8(2)3x^2-7x+2(3)4x^2+11x-3(4)2ax-1 2020-11-01 …
求一道预备班数学期中考试的答案小明在做题时发现了一个规律:1*2/1=1-2/1,2*3/1=2/1 2020-11-05 …
王怡现有2张80分和2张1.2元邮票,他最多可寄多重到哪里首重100g,每重20g不足当20g本埠0 2020-12-11 …