指数函数运算：-ln［(a-x)/(b-x)］=ln［(x-a)/(b-x)］还是ln［(b-x)/(a-x)］

Question

指数函数运算：-ln［(a-x)/(b-x)］=ln［(x-a)/(b-x)］ 还是 ln［(b-x)/(a-x)］

Answer 1

－ln[(a－x)/(b－x)]
=ln{[(a－x)/(b－x)]^(－1)}
=ln[(b－x)/(a－x)]