一个汽车队把一批水泥从工厂运到工地，第一天运了所有水泥的14又7吨，第二天运余下的25又2吨，这样还剩下全部水泥的518没有运完，问原来有多少吨水泥？

Question

(1)/(4)又7吨，第二天运余下的(2)/(5)又2吨，这样还剩下全部水泥的(5)/(18)没有运完，问原来有多少吨水泥？(1)/(4)1144(2)/(5)又2吨，这样还剩下全部水泥的(5)/(18)没有运完，问原来有多少吨水泥？(2)/(5)2255(5)/(18)没有运完，问原来有多少吨水泥？(5)/(18)551818

Answer 1

设原来水泥的总重为x吨，则第一天运了(1)/(4)x+7吨，第二天运了第二天运了（x-(1)/(4)x-7）×(2)/(5)+2吨，则：
（(1)/(4)x+7）+[（x-(1)/(4)x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (1)/(4)111444x+7吨，第二天运了第二天运了（x-(1)/(4)x-7）×(2)/(5)+2吨，则：
（(1)/(4)x+7）+[（x-(1)/(4)x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (1)/(4)111444x-7）×(2)/(5)+2吨，则：
（(1)/(4)x+7）+[（x-(1)/(4)x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (2)/(5)222555+2吨，则：
（(1)/(4)x+7）+[（x-(1)/(4)x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (1)/(4)111444x+7）+[（x-(1)/(4)x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (1)/(4)111444x-7）×(2)/(5)+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (2)/(5)222555+2]=（1-(5)/(18)）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (5)/(18)555181818）x，
             (1)/(4)x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (1)/(4)111444x+7+(3)/(10)x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (3)/(10)333101010x-(14)/(5)+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (14)/(5)141414555+2=(13)/(18)x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (13)/(18)131313181818x，
                     (11)/(20)x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (11)/(20)111111202020x+(31)/(5)=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (31)/(5)313131555=(13)/(18)x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (13)/(18)131313181818x，
                        (31)/(180)x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (31)/(180)313131180180180x=(31)/(5)
                            x=36；
答：原来有水泥36吨． (31)/(5)313131555
                            x=36；
答：原来有水泥36吨．