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matlab求积分,上下限为字母syms i I af2=i./2*log(2*I-i.*(1-cos(a)));s2=int(f2,i,0,I)运算处总是出错piecewise([cos(a) 1 and abs(arg(cos(a) - 1)) < pi and I = 1/2,log(cos(a)/2 + 1/2)/16 - (log(cos(a)/2 + 1/2)/4 - cos(a)/8 + 1/8)/(cos(a) -
题目详情
matlab求积分,上下限为字母
syms i I a
f2=i./2*log(2*I-i.*(1-cos(a)));
s2=int(f2,i,0,I)
运算处总是出错
piecewise([cos(a) 1 and abs(arg(cos(a) - 1)) < pi and I = 1/2,log(cos(a)/2 + 1/2)/16 - (log(cos(a)/2 + 1/2)/4 - cos(a)/8 + 1/8)/(cos(a) - 1)^2 - 1/32],[cos(a) 1 and abs(arg(cos(a) - 1)) < pi and I = 1/2,log(1 - sin(a/2)^2)/16 - (log(1 - sin(a/2)^2)/8 + sin(a/2)^2/8)/(2*sin(a/2)^4) - 1/32],[cos(a) = 1 or pi
syms i I a
f2=i./2*log(2*I-i.*(1-cos(a)));
s2=int(f2,i,0,I)
运算处总是出错
piecewise([cos(a) 1 and abs(arg(cos(a) - 1)) < pi and I = 1/2,log(cos(a)/2 + 1/2)/16 - (log(cos(a)/2 + 1/2)/4 - cos(a)/8 + 1/8)/(cos(a) - 1)^2 - 1/32],[cos(a) 1 and abs(arg(cos(a) - 1)) < pi and I = 1/2,log(1 - sin(a/2)^2)/16 - (log(1 - sin(a/2)^2)/8 + sin(a/2)^2/8)/(2*sin(a/2)^4) - 1/32],[cos(a) = 1 or pi
▼优质解答
答案和解析
syms i I a
f2=i/2*log(2*I-i*(1-cos(a)));
s2=int(f2,i,0,I)
s2 =
1/8*I^2*(6*cos(a)-5-6*log(I+cos(a)*I)-cos(a)^2-4*log(I+cos(a)*I)*cos(a)+2*log(I+cos(a)*I)*cos(a)^2+8*log(2)+8*log(I))/(1-2*cos(a)+cos(a)^2)
我运行下来好像没什么问题
f2=i/2*log(2*I-i*(1-cos(a)));
s2=int(f2,i,0,I)
s2 =
1/8*I^2*(6*cos(a)-5-6*log(I+cos(a)*I)-cos(a)^2-4*log(I+cos(a)*I)*cos(a)+2*log(I+cos(a)*I)*cos(a)^2+8*log(2)+8*log(I))/(1-2*cos(a)+cos(a)^2)
我运行下来好像没什么问题
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