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(2/3)^20×(-3)^20=若x^n=3,y^n=7(x^2y^3)^n=3^2m+1÷3^m-1=若3^2x-1=1,则x=计算题-2^-2-(-2)^-1-1/4+(-3)^-2
题目详情
(2/3)^20×(-3)^20=________
若x^n=3,y^n=7 (x^2y^3)^n=________
3^2m+1÷3^m-1=________
若3^2x-1=1,则x=________
计算题
-2^-2-(-2)^-1-1/4+(-3)^-2
若x^n=3,y^n=7 (x^2y^3)^n=________
3^2m+1÷3^m-1=________
若3^2x-1=1,则x=________
计算题
-2^-2-(-2)^-1-1/4+(-3)^-2
▼优质解答
答案和解析
(2/3)^20×(-3)^20=___2^20_____=[2/3×(-3)]^20=(-2)^20=2^20若x^n=3,y^n=7 (x^2y^3)^n=___3087_____=(x^n)²×(y^n)³=3²×7³=30873^2m+1÷3^m-1=_____3^(m+2)___=3^(2m+1)-(m-1)]=3^(2m+1-m...
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