（Ⅰ）计算π0+2−2×(94)−12−(0.01)0.5；（Ⅱ）计算2log510+log50.25．

Question

（Ⅰ）计算π0+2−2×((9)/(4))−(1)/(2)−(0.01)0.5；
（Ⅱ）计算2log₅10+log₅0.25．

Answer 1

（Ⅰ）π0+2−2×((9)/(4))−(1)/(2)−(0.01)0.5；
=1+(1)/(22)×[((9)/(4))−1](1)/(2)−0.01(1)/(2)
=1+(1)/(4)×[(4)/(9)](1)/(2)−((1)/(100))(1)/(2)
=1+(1)/(4)×(2)/(3)−(1)/(10)=(16)/(15)．…（6分）
（Ⅱ）2log₅10+log₅0.25
=log₅100+log₅0.25
=log₅25=2．