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一道数列题.2,11,32,().A.56B.42C.71D.134解析为幂次修正数列.2=13+1,11=23+3,32=33+5,()=43+7=71
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一道数列题.
2,11,32,( ).
A.56 B.42 C.71 D.134
【解析】为幂次修正数列.2=13 +1,11=23+3,32=33+5,()=43+7=71
2,11,32,( ).
A.56 B.42 C.71 D.134
【解析】为幂次修正数列.2=13 +1,11=23+3,32=33+5,()=43+7=71
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答案和解析
答:
【解析】为幂次修正数列.2=1^3 +1, 11=2^3+3, 32=3^3+5, ()=4^3+7=71
就是说数列通项公式为An=n^3+(2n-1)
所以:第4项是A4=4^3+(8-1)=64+7=71
n^3表示n的3次方
【解析】为幂次修正数列.2=1^3 +1, 11=2^3+3, 32=3^3+5, ()=4^3+7=71
就是说数列通项公式为An=n^3+(2n-1)
所以:第4项是A4=4^3+(8-1)=64+7=71
n^3表示n的3次方
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