因式分解：1.y^2-y-12=0 2.y(y+5)=24 3 .(x+1)^2=√2(x+1) 4 .36x^2=9(x+1)^2 5 .(x-3)^2-3(3-x)-4=0

Question

因式分解：1.y^2-y-12=0 2.y(y+5)=24 3 .(x+1)^2=√2(x+1) 4 .36x^2=9(x+1)^2 5 .(x-3)^2-3(3-x)-4=0

Answer 1

1.y^2-y-12=0
(y-4)(y+3)=0
y=4 y=-3
2.y(y+5)=24
y^2+5y-24=0
(y-3)(y+8)=0
y=3 y=-8
3 .(x+1)^2=√2(x+1)
(x+1)^2-√2(x+1)=0
(x+1)(x+1-√2)=0
x=-1 x=√2-1
4 .36x^2=9(x+1)^2
36x^2-9(x+1)^2=0
(6x+3(x+1))(6x-3(x+1))=0
(9x+3)(3x-3)=0
x=-1/3 x=1
5 .(x-3)^2-3(3-x)-4=0
(x-3)^2+3(x-3)-4=0
(x-3-1)(x-3+4)=0
x=4 x=-1