早教吧作业答案频道 -->数学-->
x+y+z=5,xy+yz+xz+7.x^2+y^2+z^2=?
题目详情
x+y+z=5,xy+yz+xz+7.x^2+y^2+z^2=?
▼优质解答
答案和解析
(x+y+z)^2=x^2+y^2+z^2+2xy+2xz+2yz=x^2+y^2+z^2+14=25 x^2+y^2+z^2=11
看了x+y+z=5,xy+yz+x...的网友还看了以下：
|x-2|+|y+3|+|z-5|=0怎么解如题,我想你们一定会答：解因为|x-2|>=0|y+3 2020-06-03 …
1.若a=10,b=8,c=6,则a、b、2c的第四比例为,a、b的比例中项x=.2.若(2-x) 2020-08-03 …
1.x+y+z≠0且x/(y+z)=y/(x+y)=z/x+y,求x/(x+y+z)2.x+y+z= 2020-10-31 …
解下列方程组:(1){2x+y-z=2,x+2y-z=5,x-y+z=-5;(2){2x+y+z=1 2020-10-31 …
(1).-3ma^3+6ma^-12ma(2).x^6n+2+2x^3n+2+x^2(3).5(x- 2020-10-31 …
因式分解,要有详细过程喔.(yz^5+zx^5+xy^5)-(zy^5+xz^5+yx^5)-(y^ 2020-11-01 …
若x+y+z=2,x^2+y^2+z^2=2,1/x+1/y+1/z=1/3则x^3+y^3+z^3 2020-11-01 …
1.若a+b=5,a^2-b^2=5求a与b的值2.已知x-y=2,y-z=2,x=z=14,求x^ 2020-11-01 …
怎么利用mathematica解三元五次方程组？如题：B1,B2,B3,u,m为已知常数，怎么利用m 2020-11-01 …
1.若2^x=5^y=10^z,xyz不等于0,则.(2^x的意思是2的x次方)A.z=(x-y)/ 2020-11-01 …