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因式分解拔高题(1)ac-bc+a^2-b^2=(2)3(x-y)m^3+27(y-x)m=(3)(y^2-1)(y+3)(y+5)-9=(4)(x+1)(x+2)(x+3)(x+4)-1=
题目详情
因式分解拔高题
(1)ac-bc+a^2-b^2=
(2)3(x-y)m^3+27(y-x)m=
(3)(y^2-1)(y+3)(y+5)-9=
(4)(x+1)(x+2)(x+3)(x+4)-1=
(1)ac-bc+a^2-b^2=
(2)3(x-y)m^3+27(y-x)m=
(3)(y^2-1)(y+3)(y+5)-9=
(4)(x+1)(x+2)(x+3)(x+4)-1=
▼优质解答
答案和解析
(1)ac-bc+a^2-b^2
=c(a-b)+(a+b)(a-b)
=(a+b+c)(a-b)
(2)3(x-y)m^3+27(y-x)m
=3(x-y)m^3-27(x-y)m
=3(x-y)m(m²-9)
=3(x-y)m(m+3)(m-3)
(3)(y^2-1)(y+3)(y+5)-9
=(y+1)(y+3)(y-1)(y+5)-9
=(y²+4y+3)(y²+4y-5)-9
=(y²+4y)²-2(y²+4y)-15-9
=(y²+4y)²-2(y²+4y)-24
=(y²+4y-6)(y²+4y+4)
=(y²+4y-6)(y+2)²
(4)(x+1)(x+2)(x+3)(x+4)-1
此题有误吧!
应该是(x+1)(x+2)(x+3)(x+4)+1
=(x+1)(x+4)(x+2)(x+3)+1
=(x²+5x+4)(x²+5x+6)+1
=(x²+5x)²+10(x²+5x)+24+1
=(x²+5x)²+10(x²+5x)+25
=(x²+5x+5)²
=c(a-b)+(a+b)(a-b)
=(a+b+c)(a-b)
(2)3(x-y)m^3+27(y-x)m
=3(x-y)m^3-27(x-y)m
=3(x-y)m(m²-9)
=3(x-y)m(m+3)(m-3)
(3)(y^2-1)(y+3)(y+5)-9
=(y+1)(y+3)(y-1)(y+5)-9
=(y²+4y+3)(y²+4y-5)-9
=(y²+4y)²-2(y²+4y)-15-9
=(y²+4y)²-2(y²+4y)-24
=(y²+4y-6)(y²+4y+4)
=(y²+4y-6)(y+2)²
(4)(x+1)(x+2)(x+3)(x+4)-1
此题有误吧!
应该是(x+1)(x+2)(x+3)(x+4)+1
=(x+1)(x+4)(x+2)(x+3)+1
=(x²+5x+4)(x²+5x+6)+1
=(x²+5x)²+10(x²+5x)+24+1
=(x²+5x)²+10(x²+5x)+25
=(x²+5x+5)²
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