早教吧作业答案频道 -->数学-->
1.(x^2-3)^2+2(x^2-3)(x-3)+(x-3)^22.(x+1)(x+3)(x+5)(x+7)+153.x^2+y^2+4x+2y+34.(a^2+a+1)^2+2(a^2+a+1)(a^2+a-1)+(a^2+a-1)^25.(x^2+4)^2-16x^2
题目详情
1.(x^2-3)^2+2(x^2-3)(x-3)+(x-3)^2
2.(x+1)(x+3)(x+5)(x+7)+15
3.x^2+y^2+4x+2y+3
4.(a^2+a+1)^2+2(a^2+a+1)(a^2+a-1)+(a^2+a-1)^2
5.(x^2+4)^2-16x^2
2.(x+1)(x+3)(x+5)(x+7)+15
3.x^2+y^2+4x+2y+3
4.(a^2+a+1)^2+2(a^2+a+1)(a^2+a-1)+(a^2+a-1)^2
5.(x^2+4)^2-16x^2
▼优质解答
答案和解析
1.原式=(x^2-3+x-3)^2=(x^2+x-6)^2=(x+3)^2(x-2)^2
2.原式=[(x+1)(x+7)][(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)^2+22(x^2+8x)+105+15
=(x^2+8x)^2+22(x^2+8x)+120
=(x^2+8x+12)(x^2+8x+10)
=(x+2)(x+6)(x^2+8x+10)
3.这道有问题,不能分解
4.原式=(a^2+a+1+a^2+a-1)^2
=(2a^2+2a)^2=4a^2(a+1)^2
5.原式=(x^2+4+4x)(x^2+4-4x)=(x+2)^2(x-2)^2
2.原式=[(x+1)(x+7)][(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)^2+22(x^2+8x)+105+15
=(x^2+8x)^2+22(x^2+8x)+120
=(x^2+8x+12)(x^2+8x+10)
=(x+2)(x+6)(x^2+8x+10)
3.这道有问题,不能分解
4.原式=(a^2+a+1+a^2+a-1)^2
=(2a^2+2a)^2=4a^2(a+1)^2
5.原式=(x^2+4+4x)(x^2+4-4x)=(x+2)^2(x-2)^2
看了 1.(x^2-3)^2+2(...的网友还看了以下:
由0,1,2,3,4,5所组成不重复的4位数(1)能被3整除的0,1,2,318种0,2,4,51 2020-04-07 …
(-1)*(-6)-(-7)*(+6)(3/4)*(1/2-4+2又2/3)-3-(-1)*(-1 2020-05-17 …
1+2+3+n=2分之1n(n+1),n是正整数,研究1*2+2*3+你(n+1),观察1*2=3 2020-05-20 …
巧算:8.7*9.9.((4.8*7.5*8.1)÷((2.4*2.5*2.7).简算::4.巧算 2020-06-11 …
若函数f(x)的定义域为1,4,则函数f(x+2)的定义域是?已知f(x)定义域为[1,4]即:1 2020-06-25 …
设非空集合A{1,2,3,4,5,6,7},且当a∈A时必有8-a∈A,这样的A共有(15)个.{ 2020-08-01 …
计算-2√3+i/1+2√3i+(√2/1+i)^2012+[(4-8i)²-(-4+8i)]/√1 2020-11-01 …
(1/2+1/3+1/4.+1/20)+(2/3+2/4.+2/20)+(3/4+3/5.+3/20 2020-11-29 …
设非空集合A{1,2,3,4,5,6,7},且当a∈A时必有8-a∈A,这样的A共有(15)个.{4 2020-12-07 …
阅读下列材料:1×2=1/3(1×2×3-0×1×2),2×3=1/3(2×3×4-1×2×3)3× 2021-01-17 …