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方程组3x+y+z=4,2x+3y-z=12,x+y+z=6解这个方程组
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方程组3x+y+z=4,2x+3y-z=12,x+y+z=6解这个方程组
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答案和解析
3x+y+z=4 (1)
2x+3y-z=12 (2)
x+y+z=6 (3)
(1)×3-(2)
7x+4z=0 (4)
(1)-(3)
2x=-2
x=-1
代入(4)
z=7/4
代入(3)
y=6-x-y=21/4
2x+3y-z=12 (2)
x+y+z=6 (3)
(1)×3-(2)
7x+4z=0 (4)
(1)-(3)
2x=-2
x=-1
代入(4)
z=7/4
代入(3)
y=6-x-y=21/4
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