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求Y(Z)=Z(Z+2)/(3Z-7)(Z+1)的z反变换
题目详情
求Y(Z)=Z(Z+2)/(3Z-7)(Z+1)的z反变换
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答案和解析
解Y(Z)=Z(Z+2)/(3Z-7)(Z+1)
Y(Z+1)=(Z+1-1)(Z+1+1)/(3(Z+1)-10)
=(Z+1)^2-1/3(Z+1)-10
所以Y(Z+1)的Z换变换为：
Y=(Z^2-1)/(3Z-10)
Y(Z+1)=(Z+1-1)(Z+1+1)/(3(Z+1)-10)
=(Z+1)^2-1/3(Z+1)-10
所以Y(Z+1)的Z换变换为：
Y=(Z^2-1)/(3Z-10)
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