因式分解本专项用”提公因式法”或”平方差,立方差(和)公式反馈.A:(1).3ab-9ac+12ad(2).25p3q3+15p2q3-5q3(3).27a3-1(4).0.81x2y2-1(5).16a2b4-9a2c2B.(6).3a(m+n)-6(m+n)(7).(m-3n)(3m+4n)+(2m-6n)(m+3n)(8).m2(a-x)+n2(x-a)(9).2a2(x-y)3

Question

因式分解
本专项用”提公因式法”或”平方差,立方差(和)公式反馈.
A:(1).3ab-9ac+12ad
(2).25p3q3+15p2q3-5q3
(3).27a3-1
(4).0.81x2y2-1
(5).16a2b4-9a2c2
B.(6).3a(m+n)-6(m+n)
(7).(m-3n)(3m+4n)+(2m-6n)(m+3n)
(8).m2(a-x)+n2(x-a)
(9).2a2(x-y)3-2ab(y-x)2
(10).(x-1)3-1
(11).(a+b)3+(a-b)3
(12).9a6b3+1/3a3b6
C:(13).xm+3-xm
(14).am+2-am-2
(15).(a+b)n+2-(a+b)n

Answer 1

A:(1).3ab-9ac+12ad =3a(b-3c+4d)
(2).25p3q3+15p2q3-5q3 =5q3 (5p3+3p2-1)
(3).27a3-1 =(3a-1)(9a^2+3a+1)
(4).0.81x2y2-1=(0.9xy-1)(0.9xy+1)
(5).16a2b4-9a2c2 =(4ab^2+3ac)(4ab^2-3ac)
B.(6).3a(m+n)-6(m+n)=3(m+n)(a+2)
(7).(m-3n)(3m+4n)+(2m-6n)(m+3n)=(m-3n)[( 3m+4n)+2(m+3n)]
=(m-3n)(5m+10n)=5(m-3n)(m+2n)
(8).m2(a-x)+n2(x-a) =(a-x)(m-n)(m+n)
(9).2a2(x-y)3-2ab(y-x)2 =2a(x-y)^2(ax-ay-b)
(10).(x-1)3-1=(x-2)[(x-1)^2+(x-1)+1]=(x-2)(x^2-x+1)
(11).(a+b)3+(a-b)3 =2a(a^2+2ab+b^2-a^2+b^2+a^2-2ab+b^2)=8ab^2
(12).9a6b3+1/3a3b6 =1/3a^3b^3(27a^3+b^3)=1/3a^3b^3(3a+b)(9a^2-3ab+b^2)
C:(13).xm+3-xm =xm(m+1)(m-1)
(14).am+2-am-2 =0
(15).(a+b)n+2-(a+b)n=(a+b)n(a+b+1)(a+b-1)