早教吧作业答案频道 -->其他-->
matlab怎么解决这个方程等于0时x的值呢,谢谢(cos(a+x)*cos(c+x)*cos(a-b))/(sin(a+c+d+x)*cos(b+x)*cos(a)^2)-(sin(a+x)*sin(c+x)*cos(a-b))/(sin(a+c+d+x)*cos(b+x)*cos(a)^2)+(cos(c+x)*sin(a+x)*sin(b+x)*cos
题目详情
matlab怎么解决这个方程等于0时x的值呢,谢谢
(cos(a + x)*cos(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) - (sin(a + x)*sin(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) + (cos(c + x)*sin(a + x)*sin(b + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)^2*cos(a)^2) - (cos(a + c + d + x)*cos(c + x)*sin(a + x)*cos(a - b))/(sin(a + c + d + x)^2*cos(b + x)*cos(a)^2)
(cos(a + x)*cos(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) - (sin(a + x)*sin(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) + (cos(c + x)*sin(a + x)*sin(b + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)^2*cos(a)^2) - (cos(a + c + d + x)*cos(c + x)*sin(a + x)*cos(a - b))/(sin(a + c + d + x)^2*cos(b + x)*cos(a)^2)
▼优质解答
答案和解析
在命令窗口输入
syms a x c b d
solve('(cos(a + x)*cos(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) - (sin(a + x)*sin(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) + (cos(c + x)*sin(a + x)*sin(b + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)^2*cos(a)^2) - (cos(a + c + d + x)*cos(c + x)*sin(a + x)*cos(a - b))/(sin(a + c + d + x)^2*cos(b + x)*cos(a)^2)=0','x')
输出答案为
2*atan(z) + 2*pi*k
syms a x c b d
solve('(cos(a + x)*cos(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) - (sin(a + x)*sin(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) + (cos(c + x)*sin(a + x)*sin(b + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)^2*cos(a)^2) - (cos(a + c + d + x)*cos(c + x)*sin(a + x)*cos(a - b))/(sin(a + c + d + x)^2*cos(b + x)*cos(a)^2)=0','x')
输出答案为
2*atan(z) + 2*pi*k
看了 matlab怎么解决这个方程...的网友还看了以下:
Matlab程序:错误在哪里建立函数文件fun5.mfunction dy=fun5(t,y)dy 2020-05-16 …
利用plot函数在区间[0,2π]同时绘制x=sin(t)和y=cos(t),z=sin(t)+c 2020-05-16 …
t为常数,x为矩阵,怎么在MATLAB中输1/t^2*exp(t*x)*sin(2*t)-1/t* 2020-05-16 …
CAXA数控车怎样画公式曲线CAXA 数控车和CAXA制造工程师的公式曲线画法怎么不一样啊?CAX 2020-06-27 …
matlab,在同一坐标轴中绘制下列两条曲线并用*标注两曲线的交点.(1)y=2x-0.5(2)x 2020-07-24 …
用matlab求定积分的上限b的值定积分l=∫(x^2+y^2+z^2)^(1/2)*xd(t)上 2020-07-24 …
已知曲线上一点(x,y),过该点做曲线的法向量n,切向量t.请问为什么cos(n,x)=cos(t 2020-07-30 …
matlab怎么解决这个方程等于0时x的值呢,谢谢(cos(a+x)*cos(c+x)*cos(a 2020-07-31 …
复数和三角函数问题sin(i*x+t)能不能表示成不含i的形式?其中i是虚数单位我本来的想法是先展 2020-08-02 …
matlab怎么解四元二次方程组x1=x3*cos(t)+y3*sin(t);y1=y3*cos(t 2020-10-31 …