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对数的运算①[log2(125)+log4(25)+log8(5)]*[log5(2)+log25(4)+log5(8)]②log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)③log5(3)=a,5^b=2,用a,b表示log54(24)
题目详情
对数的运算
①[log2(125)+log4(25)+log8(5)]*[log5(2)+log25(4)+log5(8)]
②log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)
③log5(3)=a,5^b=2,用a,b表示log54(24)
①[log2(125)+log4(25)+log8(5)]*[log5(2)+log25(4)+log5(8)]
②log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)
③log5(3)=a,5^b=2,用a,b表示log54(24)
▼优质解答
答案和解析
①
([lg5^3/lg2]+[lg5^2/lg2^2]+[lg5/lg2^3])=[3+1+(1/3)](lg5/lg2)=(13/3)(lg5/lg2)
([lg2/lg5]+[lg2^2/lg5^2]+{lg2^3/lg5]=[1+1+3](lg2/lg5)=5(lg2/lg5)
原式=[(13/3)(lg5/lg2)]*[5(lg2/lg5)]=65/3
②
原式=(lg3/lg2)(lg4/lg3)(lg5/lg4)(lg6/lg5)(lg7/lg6)(lg8/lg7)
=lg8/lg2=3
③
log5(3)=a ; log5(2)=b;
log54(24)=log5(3*2^3)/log5(2*3^3)=[log5(3)+3log5(2)]/[log5(2)+3log5(3)]
=(a+3b)(b+3a)
([lg5^3/lg2]+[lg5^2/lg2^2]+[lg5/lg2^3])=[3+1+(1/3)](lg5/lg2)=(13/3)(lg5/lg2)
([lg2/lg5]+[lg2^2/lg5^2]+{lg2^3/lg5]=[1+1+3](lg2/lg5)=5(lg2/lg5)
原式=[(13/3)(lg5/lg2)]*[5(lg2/lg5)]=65/3
②
原式=(lg3/lg2)(lg4/lg3)(lg5/lg4)(lg6/lg5)(lg7/lg6)(lg8/lg7)
=lg8/lg2=3
③
log5(3)=a ; log5(2)=b;
log54(24)=log5(3*2^3)/log5(2*3^3)=[log5(3)+3log5(2)]/[log5(2)+3log5(3)]
=(a+3b)(b+3a)
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