问一道整式题[2(x-y)^5+4(x-y)^4+6(y-x)^3]/2(x-y)^2^是幂6^5意思是六的五次方

Question

问一道整式题
[2(x-y)^5+4(x-y)^4+6(y-x)^3]/2(x-y)^2
^是幂
6^5意思是六的五次方

Answer 1

[2(x-y)^5+4(x-y)^4+6(y-x)^3]/2(x-y)^2
=[2(x-y)^5+4(x-y)^4-6(x-y)^3]/2(x-y)^2
=2(x-y)^5/2(x-y)^2+4(x-y)^4/2(x-y)^2-6(x-y)^3/2(x-y)^2
=(x-y)^2+2(x-y)-3
=x^2-2xy+y^2-2x-2y-3