多项式−5x2y3+12x3y2−4xy−1−π2x4y2按字母x的降幂排列为−π2x4y2+12x3y2-5x2y3-4xy-1−π2x4y2+12x3y2-5x2y3-4xy-1；最高次项是−π2x4y2−π2x4y2．

Question

多项式−5x2y3+(1)/(2)x3y2−4xy−1−(π)/(2)x4y2按字母x的降幂排列为

−(π)/(2)x⁴y²+(1)/(2)x³y²-5x²y³-4xy-1

−(π)/(2)x⁴y²+(1)/(2)x³y²-5x²y³-4xy-1

；最高次项是

−(π)/(2)x⁴y²

−(π)/(2)x⁴y²

．

Answer 1

把多项式−5x2y3+(1)/(2)x3y2−4xy−1−(π)/(2)x4y2按字母x的降幂排列为−(π)/(2)x⁴y²+(1)/(2)x³y²-5x²y³-4xy-1；
最高次项为−(π)/(2)x⁴y²．