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x的平方加xy加y的平方等于27,求x
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x的平方加xy加y的平方等于27,求x
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答案和解析
x^2+xy+y^2-27=0
X1=[-Y+√(Y^2-4Y^2+108)]/2
=[-Y+√(108-3Y^2)]/2
X1=[-Y+√3√(36-Y^2)]/2 (1)
X2=[-Y-√(108-3Y^2)]/2
=-[Y+√3√(36-Y^2)]/2 (2)
(1)(2)为本问题的解,为了得到实数解,Y
X1=[-Y+√(Y^2-4Y^2+108)]/2
=[-Y+√(108-3Y^2)]/2
X1=[-Y+√3√(36-Y^2)]/2 (1)
X2=[-Y-√(108-3Y^2)]/2
=-[Y+√3√(36-Y^2)]/2 (2)
(1)(2)为本问题的解,为了得到实数解,Y
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