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y=(x-1)*立方根(x+2)/(x-3)^(2)*e^(2x)求dy

题目详情
y=(x-1) * 立方根(x+2) / (x-3)^(2) * e^(2x) 求dy
▼优质解答
答案和解析
dy=(x+2)^(1/3)/(x-3)²e^2xdx+1/3*(x-1)(x+2)^(-2/3)/(x-3)²e^2xdx-2(x-1)(x+2)^(1/3)/(x-3)³e^2xdx+2(x-1)(x+2)^(1/3)/(x-3)²e^2xdx
=[(x+2)^(1/3)/(x-3)²e^2x+1/3*(x-1)(x+2)^(-2/3)/(x-3)²e^2x-2(x-1)(x+2)^(1/3)/(x-3)³e^2x+2(x-1)(x+2)^(1/3)/(x-3)²e^2x]dx