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一道初中整式问题ax+by=7ax^2+by^2=49ax^3+by^3=133ax^4+by^4=406求2008（x+y）+2008xy+(a+b)/21
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∵ax＋by＝7,∴（ax＋by）（x＋y）＝ax^2＋axy＋bxy＋by^2＝（ax^2＋by^2）＋xy（a＋b）.又ax^2＋by^2＝49, ∴7（x＋y）＝49＋xy（a＋b）.······①∵ax^2＋by^2＝49,∴（ax^2＋by^2）（x＋y）＝ax^3＋ax^2y＋...
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