早教吧作业答案频道 -->数学-->
z∧3-3xyz=a∧3,求先对x偏导再对y的二阶偏导.答案是z(z∧4-2xyz∧2-x∧2y∧2)/(z∧2...z∧3-3xyz=a∧3,求先对x偏导再对y的二阶偏导.答案是z(z∧4-2xyz∧2-x∧2y∧2)/(z∧2-xy)∧3..我解了很多遍
题目详情
z∧3-3xyz=a∧3,求先对x偏导再对y的二阶偏导.答案是z(z∧4-2xyz∧2-x∧2y∧2)/(z∧2...
z∧3-3xyz=a∧3,求先对x偏导再对y的二阶偏导.答案是z(z∧4-2xyz∧2-x∧2y∧2)/(z∧2-xy)∧3..我解了很多遍就是没有解到z∧4?
z∧3-3xyz=a∧3,求先对x偏导再对y的二阶偏导.答案是z(z∧4-2xyz∧2-x∧2y∧2)/(z∧2-xy)∧3..我解了很多遍就是没有解到z∧4?
▼优质解答
答案和解析
运用隐函数求导法则,两端对x求导得
用隐函数微分法
令F[x,y,z] = z³-3xyz-a³
z'x = -F'x/F'z = yz/(z²-xy)
z'y = -F'y/F'z = xz/(z²-xy)
z''xy = [z'x]'y = [(yz)'(z² - xy) - yz * (2z z'y - x)]/(z²-xy)²
= [(z + y z'y)(z²-xy) - 2yz² z'y + xyz]/(z²-xy)²
= (z³ - yz² z'y - xy² z'y)/(z²-xy)²
= [z³ - (yz²+xy²)xz/(z²-xy)]/(z²-xy)²
= z(z^4 - 2xyz³ - x²y²z)/(z²-xy)³
用隐函数微分法
令F[x,y,z] = z³-3xyz-a³
z'x = -F'x/F'z = yz/(z²-xy)
z'y = -F'y/F'z = xz/(z²-xy)
z''xy = [z'x]'y = [(yz)'(z² - xy) - yz * (2z z'y - x)]/(z²-xy)²
= [(z + y z'y)(z²-xy) - 2yz² z'y + xyz]/(z²-xy)²
= (z³ - yz² z'y - xy² z'y)/(z²-xy)²
= [z³ - (yz²+xy²)xz/(z²-xy)]/(z²-xy)²
= z(z^4 - 2xyz³ - x²y²z)/(z²-xy)³
看了 z∧3-3xyz=a∧3,求...的网友还看了以下:
已知x,y,z满足y+z/x=z+x/y=x+y/z=k,求k的值我只知道一个,∵y+z/x=z+ 2020-04-26 …
线性规划数学题:实数x,y满足x-y+1≤0,x>0,y≤2,若实数x,y满足x-y+1≤0,x> 2020-05-16 …
偏导数双李复习全书的多元函数的习题:已知z=z(x,y)后面说由z=z(x,y)可解出y=y(z, 2020-05-21 …
x+y+z=36x-y=12x+z-y=18x+y+z=26①x-y=1②2x+z-y=18③x+ 2020-06-06 …
实数x,y满足x-y+1≤0,x>0,y≤2(1)若z=y/x,求z的取值范围(2)若z=x平方+ 2020-07-26 …
(a+b+c)/3大于等于3*√abc设a=x^3,b=y^3,c=z^3x,y,z是非负数时x^3 2020-11-01 …
1.f(x-z,y-z)=0,其中f(u,v)是可微函数,证明:偏z/偏x+偏z/偏y=12.设z= 2020-11-01 …
已知(y+z-x)/(x+y+z)=(z+x-y)/(y+z-x)=(x+y-z)/(z+x-y)= 2020-11-01 …
有理数X.Y.Z互不相等且X+1/Y=Y+1/Z=Z+1/X,求证XYZ的平方等于一有理数X.Y.Z 2020-11-07 …
概率统计问题条件概率与期望:为什么E[(XE(Y|Z))|Z]=E(X|Z)E(Y|Z)?概率统计问 2020-12-01 …