早教吧作业答案频道 -->英语-->
对某人期望很高后面加for还是of?关于haveexpectation都有什么用法
题目详情
对某人期望很高后面加for还是of?
关于have expectation都有什么用法
关于have expectation都有什么用法
▼优质解答
答案和解析
have expectation of 和have expectation for 都有的.
例句与用法:
1.He has great expectations from his uncle.
他渴望从叔叔那继承大笔遗产.
2.She ate a light lunch in expectation of a good dinner.
她午饭吃得很少,期待晚饭时饱餐一顿.
3.His parents have great expectations for his future.
他父母对他的前途深寄厚望.
4.He has little expectation of winning a prize.
他对获奖不抱什麽希望.
5.She had high expectations of what university had to offer.
她对大学所能给她提供的一切期望很高.
6.The children waited patiently in expectation of (ie expecting) the magician.
孩子们耐心地等待著魔术师.
7.His film performance didn't come up to expectations.
他在影片中的演出有负众望.
8.Unfortunately the restaurant he recommended fell far short of our expectations.
遗憾的是他推荐的餐厅与我们心目中的相去甚远
例句与用法:
1.He has great expectations from his uncle.
他渴望从叔叔那继承大笔遗产.
2.She ate a light lunch in expectation of a good dinner.
她午饭吃得很少,期待晚饭时饱餐一顿.
3.His parents have great expectations for his future.
他父母对他的前途深寄厚望.
4.He has little expectation of winning a prize.
他对获奖不抱什麽希望.
5.She had high expectations of what university had to offer.
她对大学所能给她提供的一切期望很高.
6.The children waited patiently in expectation of (ie expecting) the magician.
孩子们耐心地等待著魔术师.
7.His film performance didn't come up to expectations.
他在影片中的演出有负众望.
8.Unfortunately the restaurant he recommended fell far short of our expectations.
遗憾的是他推荐的餐厅与我们心目中的相去甚远
看了 对某人期望很高后面加for还...的网友还看了以下:
已知函数fx=ax(e^x+e^-x)是R上的偶函数,则常数a= 2020-05-13 …
设a>0,f(x)=e^x/a+a/e^x是R上的偶函数,求a的值. 2020-05-16 …
设a>0,f(x)=e^x/a+a/e^x是R上的偶函数1.求a的值2.证明:f(x)在(0,+无 2020-05-16 …
设a>0,f(x)=e^x/a+a/e^x是R上的偶函数,求a值.∵f(x)=e^x/a+a/e^ 2020-05-17 …
设有关系模式R(A,B,C,D,E),F是R上成立的函数依赖集,F={ABC→D,B→D,D→E}, 2020-05-23 …
设a>0,f(x)=(e^x)/a+a/(e^x)是R上的增函数.(1)求a的值(2)证明f(x) 2020-06-05 …
设a>0,f(x)=e^x/a+a/e^x是R上的偶函数,证明:f(x)在(0,+无穷)上是增函数 2020-08-01 …
设a>0,f(x)=e^x/a+a/e^x是R上的偶函数(其中e≥2.71828)(1)求a的值; 2020-08-01 …
E=hγ是否仅适用于光子?由p=mv=h/λ与E=hγ=mc^2得物质波波速V=c^2/v这个V明显 2020-11-25 …
E=hγ是否仅适用于光子?由p=mv=h/λ与E=hγ=mc^2得物质波波速V=c^2/v这个V明显 2020-12-09 …