对方程的左边对x求导//y'是怎么求出来的?对方程x³-3xy²+2y³-32=0的左边对x求导,得3x²-3y²-6xy·y'+6y²·y'=0

Answer 1

(x³)'=3x²
(-3xy²)'
=-3*(xy²)'
=-3*(x'*y²+x*(y²)')
=-3*(1*y+x*2y*y')
=-3*(y+2xy*y')
(2y³)'
=2*3y²*y'
=6y²*y'
(-32)'=0
加起来即可