ab=1,则(a^n-b^n)^2-(a^n+b^n)^2=求此题解答~

Question

ab=1,则(a^n-b^n)^2-(a^n+b^n)^2=____ 求此题解答~

Answer 1

(a^n-b^n)^2-(a^n+b^n)^2
=(a^n-b^n+a^n+b^n)(a^n-b^n-a^n-b^n)
=2a^n×(-2b^n)
=-4(ab)^n
=-4
这是我在静心思考后得出的结论,
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