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计算下面各题,能用简便方法计算的要用简便方法计算.936-1365÷13+95(518÷13+518)×0.251350×49+87×4950(34:3-110)×(2-23)

题目详情
计算下面各题,能用简便方法计算的要用简便方法计算.
936-1365÷13+95
5
18
÷
1
3
+
5
18
)×0.25
13
50
×49+87×
49
50
3
4
:3-
1
10
)×(2-
2
3
936-1365÷13+95
5
18
÷
1
3
+
5
18
)×0.25
13
50
×49+87×
49
50
3
4
:3-
1
10
)×(2-
2
3
936-1365÷13+95 (
5
18
÷
1
3
+
5
18
)×0.25
936-1365÷13+95(
5
18
÷
1
3
+
5
18
)×0.25
5
18
÷
1
3
+
5
18
)×0.25
5
18
551818
1
3
+
5
18
)×0.25
1
3
1133
5
18
)×0.25
5
18
551818
13
50
×49+87×
49
50
3
4
:3-
1
10
)×(2-
2
3
13
50
×49+87×
49
50
13
50
×49+87×
49
50
13
50
13135050
49
50
49
50
49495050(
3
4
:3-
1
10
)×(2-
2
3
3
4
:3-
1
10
)×(2-
2
3
3
4
3344
1
10
)×(2-
2
3
1
10
111010
2
3
2
3
2233
▼优质解答
答案和解析
(1)936-1365÷13+95,
=936-105+95,
=831+95,
=926;

(2)(
5
18
÷
1
3
+
5
18
)×0.25,
=(
15
18
+
5
18
)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
5
18
555181818÷
1
3
+
5
18
)×0.25,
=(
15
18
+
5
18
)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
1
3
111333+
5
18
)×0.25,
=(
15
18
+
5
18
)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
5
18
555181818)×0.25,
=(
15
18
+
5
18
)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
15
18
151515181818+
5
18
)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
5
18
555181818)×0.25,
=
20
18
×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
20
18
202020181818×
1
4

=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
1
4
111444,
=
5
18


(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
5
18
555181818;

(3)
13
50
×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
13
50
131313505050×49+87×
49
50

=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
49
50
494949505050,
=13×
49
50
+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
49
50
494949505050+87×
49
50

=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
49
50
494949505050,
=(13+87)×
49
50

=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
49
50
494949505050,
=98;

(4)(
3
4
:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
3
4
333444:3-
1
10
)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
1
10
111101010)×(2-
2
3
),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
2
3
222333),
=(
1
4
-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
1
4
111444-
1
10
)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
1
10
111101010)×(2-
2
3
),
=
3
20
×
4
3

=
1
5
2
3
222333),
=
3
20
×
4
3

=
1
5
3
20
333202020×
4
3

=
1
5
4
3
444333,
=
1
5
1
5
111555.