计算:(1)−12+12÷[(−112)3+(−12)2]×|−2.52|−12;(2)(−1)5×{[423÷(−4)+(−114)×(−0.4)]÷(−13)−2};(3)[(1−13)2−(−123)÷(−118)]×(−112)3+512×(−511);(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(
−+÷[(−1)3+(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 2 |
2 | 1 |
1 | 2 |
2 | (−1)3+(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(−1)3+(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 2 |
2 | 3+(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(−)2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 2 |
2 | 2]×|−2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2.52|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2|−;
(2)(−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 2 |
2 | (−1)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].)5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].5×{[4÷(−4)+(−1)×(−0.4)]÷(−)−2};
(3)[(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2 |
2 | 3 |
3 | 1 |
1 | 4 |
4 | 1 |
1 | 3 |
3 | [(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(1−)2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 3 |
3 | 2−(−1)÷(−1)]×(−1)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2 |
2 | 3 |
3 | 1 |
1 | 8 |
8 | 1 |
1 | 2 |
2 | )3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].)3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].3+5×(−);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].1 |
1 | 2 |
2 | 5 |
5 | 11 |
11 | {[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].{[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].{[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2×10−0.09]2×100−0.009}2×[(−2)3+2×3].2×100−0.009}2×[(−2)3+2×3].2×[(−2)3+2×3].(−2)3+2×3].(−2)3+2×3].3+2×3].2 |
2 | 3 |
3 |
答案和解析
(1)原式=-
+÷[-+]×6.25-
=-1+×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
2 |
2 | 2+
÷[-+]×6.25-
=-1+×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
2 |
2 | 2÷[-
+]×6.25-
=-1+×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 27 |
27 | 27
8 |
8 | 8+
]×6.25-
=-1+×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
4 |
4 | 4]×6.25-
=-1+×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
2 |
2 | 2
=-1+
×(-)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
2 |
2 | 2×(-
)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 8 |
8 | 8
25 |
25 | 25)×
=-1-1
=-2;
(2)原式=-1×{[×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 25 |
25 | 25
4 |
4 | 4
=-1-1
=-2;
(2)原式=-1×{[
×(-)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 14 |
14 | 14
3 |
3 | 3×(-
)+×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
4 |
4 | 4)+
×]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 5 |
5 | 5
4 |
4 | 4×
]÷(-)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 2 |
2 | 2
5 |
5 | 5]÷(-
)-2}
=-1×{[-+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
3 |
3 | 3)-2}
=-1×{[-
+]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 7 |
7 | 7
6 |
6 | 6+
]÷(-)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
2 |
2 | 2]÷(-
)-2}
=-1×{-×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 1 |
1 | 1
3 |
3 | 3)-2}
=-1×{-
×(-3)-2}
=-1×0
=0;
(3)原式=[-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 2 |
2 | 2
3 |
3 | 3×(-3)-2}
=-1×0
=0;
(3)原式=[
-×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 4 |
4 | 4
9 |
9 | 9-
×]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 5 |
5 | 5
3 |
3 | 3×
]×(-)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 8 |
8 | 8
9 |
9 | 9]×(-
)+×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 27 |
27 | 27
8 |
8 | 8)+
×(-)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 11 |
11 | 11
2 |
2 | 2×(-
)
=-×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 5 |
5 | 5
11 |
11 | 11)
=-
×(-)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 28 |
28 | 28
27 |
27 | 27×(-
)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 27 |
27 | 27
8 |
8 | 8)-
=-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 5 |
5 | 5
2 |
2 | 2
=
-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 7 |
7 | 7
2 |
2 | 2-
=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0. 5 |
5 | 5
2 |
2 | 2
=1;
(4)原式={[0.01×10-0.09]
22×100-0.009}
22×(-8+8)
={[0.01×10-0.09]
22×100-0.009}
22×0
=0.
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