ansyscm,rotor1,elemALLSEL,ALLDK,1,0,ux,uy,uz,rotz,ALLSEL,ALLDK,6,0,ux,uy,rotz,ALLSEL,ALLDK,ALL,0,rotzf0=5.1e-3fk,2,fx,f0,0fk,2,fy,0,-f0f1=5.1e-3fk,4,fx,-f1,0fk,4,fy,0,f1/SOLUantype,harmicdmprat,0.000001synchro,rotor1coriolis,on,onnsubst,200harf

Question

ansys
cm,rotor1,elem
ALLSEL,ALL
DK,1,0,ux,uy,uz,rotz,
ALLSEL,ALL
DK,6,0,ux,uy,rotz,
ALLSEL,ALL
DK,ALL,0,rotz
f0=5.1e-3
fk,2,fx,f0,0
fk,2,fy,0,-f0
f1=5.1e-3
fk,4,fx,-f1,0
fk,4,fy,0,f1
/SOLU
antype,harmic
dmprat,0.000001
synchro,rotor1
coriolis,on,on
nsubst,200
harfrq,0,200
cmomega,rotor1,250
kbc,1
solve
finish
这段代码里面cm,rotor1,做谐分析为什么还要定义转速,cmomega,rotor1,250是多余的吗,有什么用?

Answer 1

cm是定义组件的命令,将一部分单元定义成一个组件,直接对组件施加边界条件,转速的问题不清楚,没做过之类问题