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计算(0.1+0.12+0.123+0.1234)×(0.12+0.123+0.1234+0.12345)-(0.1+0.12+0.123+0.1234+0.12345)×(0.12+0.123+0.1234)
题目详情
计算 (0.1+0.12+0.123+0.1234)×(0.12+0.123+0.1234+0.12345)-(0.1+0.12+0.123+0.1234+0.12345)×(0.12+0.123+0.1234) |
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答案和解析
设(0.1+0.12+0.123+0.1234)=A,(0.12+0.123+0.1234)=B,则A-B=0.1, (0.1+0.12+0.123+0.1234)×(0.12+0.123+0.1234+0.12345)-(0.1+0.12+0.123+0.1234+0.12345)×(0.12+0.123+0.1234) =A×(B+0.12345)-(A+0.12345)×B =AB+0.12345A-(AB+0.12345B) =AB+0.12345A-AB-0.12345B =0.12345×(A-B) =0.12345×0.1 =0.012345. |
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