matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')

Question

matlab 超越方程
e1=(1.09+13.43*i)^2
e2=2.25
k0 =3.2429
a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]
k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')

Answer 1

这类题可以用solve()函数,只能一个一个地求.求解方法如下：