早教吧作业答案频道 -->数学-->
1.(5x^2y^3)^2÷(25x^4y^5)2.(x+y)^3÷(x+y)3.(7a^5b^3c^5)÷(14a^2b^3c)4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)用整式除法计算,
题目详情
1.(5x^2y^3)^2÷(25x^4y^5)
2.(x+y)^3÷(x+y)
3.(7a^5b^3c^5)÷(14a^2b^3c)
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
用整式除法计算,
2.(x+y)^3÷(x+y)
3.(7a^5b^3c^5)÷(14a^2b^3c)
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
用整式除法计算,
▼优质解答
答案和解析
1.(5x^2y^3)^2÷(25x^4y^5)
=25x^4y^6÷(25x^4y^5)
=y^6÷y^5
=y
2.(x+y)^3÷(x+y)
=(x+y)^(3-1)
=(x+y)^2
3.(7a^5b^3c^5)÷(14a^2b^3c)
=(7÷14)*a^(5-2)b^(3-3)c^(5-1)
=1/2a^3c^4
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
=[8÷2*(-2/3)]*a^(4-2+3)b^(3-3+1)c^(1+2)
=[4*(-2/3)]*a^5bc^3
=-8/3a^5bc^3
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
=(3x^2y)·(15xy^3)÷(9x^4y^2)
=(3*15÷9)x^(2+1-4)y^(1+3-2)
=(45÷9)x^(-1)y^2
=5x^(-1)y^2
=5y^2/x
=25x^4y^6÷(25x^4y^5)
=y^6÷y^5
=y
2.(x+y)^3÷(x+y)
=(x+y)^(3-1)
=(x+y)^2
3.(7a^5b^3c^5)÷(14a^2b^3c)
=(7÷14)*a^(5-2)b^(3-3)c^(5-1)
=1/2a^3c^4
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
=[8÷2*(-2/3)]*a^(4-2+3)b^(3-3+1)c^(1+2)
=[4*(-2/3)]*a^5bc^3
=-8/3a^5bc^3
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
=(3x^2y)·(15xy^3)÷(9x^4y^2)
=(3*15÷9)x^(2+1-4)y^(1+3-2)
=(45÷9)x^(-1)y^2
=5x^(-1)y^2
=5y^2/x
看了1.(5x^2y^3)^2÷(...的网友还看了以下：
急急急1.下列多项式相乘,不能用平方差公式计算的是（）A.(x-2y)(2y-x)B.(x-2y) 2020-05-13 …
1.（－2a）³·b²÷(8a³b²)2.－5x（2x²－3x＋4）+4x³+15x3.（x²-2 2020-06-03 …
先化简,再求值大侠们1求5x^2-[3y^2+7xy]+[2y^2-5x^2]的值,其中x=0.1 2020-06-05 …
2a^3-8a^2+8a 分解因式（1）2a^3-8a^2+8a（2）a^3-4AB^2(3)2a 2020-06-27 …
把下列各式分解因式;在下面在下面在下面.（1）4ab^2-8a^2b;(2)-15xy-5x^2; 2020-07-09 …
分解因式1）x^2y^2+xy-122）(x-y)^2-6x+6y+93）-8a^3b^2+12a 2020-07-18 …
(x-y)(x+y)()=x^4n-2x^2y^2+y^4=2a^2b^2(+-)=2a^2b^2 2020-08-01 …
求解题目十字相乘法分解因式1.a^3-5a^2-6a=2.y^2-8y+7=3.x^2*y^2-6 2020-08-03 …
小明在解决问题：已知a=12+3，求2a2-8a+1的值，他是这样分析与解答的：∵a=12+3=2- 2020-10-31 …
已知函数f(x)＝sin^2x+acosx+5/8a-3/2,a∈R（1当a=1,求函数f(x)最大 2020-12-08 …