早教吧作业答案频道 -->数学-->
1.xy(x^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)2.(y+z)(z+x)(x+y)+xyz是因式分解
题目详情
1.xy(x^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
2.(y+z)(z+x)(x+y)+xyz
是因式分解
2.(y+z)(z+x)(x+y)+xyz
是因式分解
▼优质解答
答案和解析
1.xy(x^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
=xy(x^2-z^2+z^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
=xy(x^2-z^2)+xy(z^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
=(z^2-x^2)(zx-xy)+(y^2-z^2)(yz-xy)
=(z-x)(z-y)(x(z+x)-y(y+z))
=(z-x)(z-y)(z(x-y)+(x+y)(x-y))
=(z-x)(z-y)(x-y)(x+y+z)
2.(y+z)(z+x)(x+y)+xyz
=(x+y+z-x)(z+x)(x+y)+xyz
=(x+y+z)(z+x)(x+y)-x(z+x)(x+y)+xyz
=(x+y+z)(z+x)(x+y)-x^2z-x^3-x^2y
=(x+y+z)(z+x)(x+y)-x^2(x+y+z)
=(x+y+z)(xz+zy+xy)
=xy(x^2-z^2+z^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
=xy(x^2-z^2)+xy(z^2-y^2)+yz(y^2-z^2)+zx(z^2-x^2)
=(z^2-x^2)(zx-xy)+(y^2-z^2)(yz-xy)
=(z-x)(z-y)(x(z+x)-y(y+z))
=(z-x)(z-y)(z(x-y)+(x+y)(x-y))
=(z-x)(z-y)(x-y)(x+y+z)
2.(y+z)(z+x)(x+y)+xyz
=(x+y+z-x)(z+x)(x+y)+xyz
=(x+y+z)(z+x)(x+y)-x(z+x)(x+y)+xyz
=(x+y+z)(z+x)(x+y)-x^2z-x^3-x^2y
=(x+y+z)(z+x)(x+y)-x^2(x+y+z)
=(x+y+z)(xz+zy+xy)
看了1.xy(x^2-y^2)+y...的网友还看了以下:
偏导数函数不会打就用&代替了Z=2^xy方,则&z/&x&y=多少这个题目我写后答案的开头首先是这样 2020-03-30 …
用max{a,b,c}表示a,b,c中的最大者,若x,y,z均为正数,则{x^2+y^2,xy+z 2020-04-27 …
x+y=2,xy-z的平方-4z=5,求XYZ的值 2020-06-12 …
已知隐函数z=(x,y)由方程x^2-xy+z^3=1所确定,求ðz/ðx和ðz/ðy题中为什么设 2020-06-12 …
1..设x/a+y/b+z/c=1,a/x+b/y+c/z=0,求x*2/a*2+y*2/b*2+z 2020-10-30 …
xyz=1,x+y+z=2,x^2+y^2+z^2=3,求x,y,z我解:xy=1/z,x+y=2- 2020-10-31 …
1.x+y+z≠0且x/(y+z)=y/(x+y)=z/x+y,求x/(x+y+z)2.x+y+z= 2020-10-31 …
若x,y,z∈(0,1)且xy+yz+xz=1求证y/(2-√3x)+z/(2-√3y)+若x,y, 2020-11-01 …
1.(x+2y+z)^3-(x+y)^3-(y+z)^32.1+x+y+z+xy+yz+xz+xyz 2020-11-01 …
设实数x>0,y>0,z>0,a>0,b>0,且x,y,z满足条件x^2+y^2-xy=a^2;x^ 2020-11-01 …