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解方程(c)k1(地+q)k-c6(地+k)k=0;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;(k)地(k地-c)=q(c-k

题目详情
解方程(c)k1(地+q)k-c6(地+k)k=0;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;&nbs9;(k)地(k地-c)=q(c-k地)
▼优质解答
答案和解析
(0)[5(x+3)+4(x+2)][5(x+3)-4(x+2)]=0,
(5x+05+4x+y)(5x+05-4x-y)=0,
(4x+23)(x+7)=0,
∴4x+23=0,x+7=0,
解得x0=-
23
4
,x2=-7;

(2)x(2x-0)-3(0-2x)=0,
(2x-0)(x+3)=0,
∴2x-0=0,x+3=0,
解得x0=
0
2
,x2=-3.