设x3＝y4＝z2，则x−2y+3zx−3y−z=．

Question

设(x)/(3)＝(y)/(4)＝(z)/(2)，则(x−2y+3z)/(x−3y−z)=______．

Answer 1

设(x)/(3)＝(y)/(4)＝(z)/(2)=k，
则x=3k，y=4k，z=2k．
则(x−2y+3z)/(x−3y−z)=(3k−8k+6k)/(3k−12k−2k)＝(k)/(−11k)＝−(1)/(11)．
故答案为-(1)/(11)．