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求函数z=x^2ln(x^2+y^2)的一阶偏导数
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求函数z=x^2ln(x^2+y^2)的一阶偏导数
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答案和解析
Z'x=2xln(x^2+y^2)+x^2/(x^2+y^2)*2x=2xln(x^2+y^2)+2x^3/(x^2+y^2)
Z'y=x^2/(x^2+y^2)*2y=2x^2y/(x^2+y^2)
Z'y=x^2/(x^2+y^2)*2y=2x^2y/(x^2+y^2)
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