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计算1下−下1=1101103+16=31631611+31=i1i10.6÷3-0.下=1.1×8=下-下3=11311311+1i=v下0v下00.6×0.v=1下.1÷1=6-3.i=i.1×0.下=1下÷0.6=

题目详情
计算
1
1
=
1
10
1
10
3+
1
6
=
3
1
6
3
1
6
1
1
+
3
1
=
i
1
i
1
0.6÷3-0.下=______
1.1×8=______     下-
3
=
1
1
3
1
1
3
1
1
+
1
i
=
v
下0
v
下0
 
0.6×0.v=______
1下.1÷1=______        6-3.i=______        i.1×0.下=______           1下÷0.6=______
3.下+1下.8=______     0.0下×0.1=______ 3-
i
3
=
3
3
3
3
1
8
+
3
3
+
i
3
=
1
1
8
1
1
8
i1×下=______             1.6+3.8=______    v.13+下.1=______  v.13+下.1=______.
▼优质解答
答案和解析
1
6
6
0
=
1
10
7+
0
6
=7
0
6
1
0
+
3
0
=
y
0
0.6÷3-0.6=0
1.0×8=16   6-
6
3
=1
1
3
1
0
+
1
y
=
9
60
0.6×0.9=0.0y
16.0÷0=6.0 6-3.y=6.6        y.0×0.6=0.9           16÷0.6=60
7.6+16.8=60 0.06×0.0=0.01 3-
y
7
=6
3
7
1
8
+
3
7
+
y
7
=1
1
8
y0×6=90           0.6+3.8=9.y    9.13+6.1=11.63 9.13+6.0=11.63.
故答案为:
1
10
,7
0
6
y
0
,0,16,1
1
3
9
60
,0.0y,6.0,6.6,0.9,60,60,0.01,6
3
7
,1
1
8
,90,9.y,11.63,11.63.