MordernPhysics(a)AccordingaobserverO,acertainparticlehasamomentumof817MeV/candatotalrelativisticenergyof1125MeV.Whatistherestenergyofthisparticle?根据观测者O,一个粒子的动量为817MeV/c,总相对能量为1125Mev.

Question

Mordern Physics
(a) According a observer O,a certain particle has a momentum of 817 MeV/c and a total relativistic energy of 1125 MeV.What is the rest energy of this particle?根据观测者O,一个粒子的动量为817MeV/c,总相对能量为1125Mev.求Rest energy.
(b)An observer O' in a different frame of reference measures the momentum of this particle to be 953 MeV/c.What does O' measure for the total relativistic energy of the particle?
根据观测者O’,在不同的体系中测量到的该粒子动量为953MeV/c.求观测者O‘ 观测到的总相对能量.

Answer 1

(a)相对能量公式为,E=根号下(p^2*c^2+m0^2*c^4)
已知E和p,求出Rest Energy=m0c^2=根号下(E^2-p^2*c^2)=773.4MeV
(b)在不同参考系下,Rest Energy是不变的,即p‘c=953,m0*c^2=773.4
根据公式,E=根号下(p’^2*c^2+m0^2*c^4)=1227.3MeV