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..Okayso~Showthenetionicreactionequationsfortheneutralizationofbenzoicacidwithpotassiumsulfite.Balance过后的molecularequation是:2(C6H5COOH)+K2SO3→2K(C6H5COOH)+SO3那么它的netionicequation该怎么写呢?哪几个是spectato

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Okay so~Show the net ionic reaction equations for the neutralization of benzoic acid with potassium sulfite.Balance过后的molecular equation是:2(C6H5COOH)+K2SO3→2K(C6H5COOH)+SO3那么它的net ionic equation该怎么写呢?哪几个是spectator?Show the net ionic reaction equations for the neutralization of sodium hydrogen sulfate (acid) with lithium hydroxide.Balance过后的molecular equation是:NaHSO4+LiOH→NaOH+LiHSO4这是我写的第一步的net ionic equation…Na+HSO4+Li+OH→Na+OH+Li+HSO4我不知道对不对,但是如果对的话,那岂不4个全是spectator?那不全都给eliminate了?I don’t get it…求教下高手...本人化学不咋地...
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答案和解析
第一个2(C6H5COOH)+K2SO3→2(C6H5COOK)+SO2↑+H2O
弱酸不拆,可溶盐拆,有2(C6H5COOH)+2(K+)+(SO3)2-→2C6H5COO-+2(K+)+SO2↑+H2O
2(C6H5COOH)+(SO3)2-→2(C6H5COO-)+SO2↑+H2O
第二个
NaHSO4+LiOH=LiNaSO4+H2O
HSO4-有的必须拆,有的可以不拆,不同的地方有不同的要求,一般还是拆掉
关键在于LiOH是否是强碱,说法不一,我个人认为是,那么得(H+)+OH-=H2O