一人给第一个乞丐口袋钱一半加一元,给第二乞丐剩下钱的一半加二元,给第三乞丐剩下钱的一半加三元.这个人口袋只剩一元钱,请问这个人原先口袋有多少钱.

Question

一人给第一个乞丐口袋钱一半加一元,给第二乞丐剩下钱的一半加二元,
给第三乞丐剩下钱的一半加三元.这个人口袋只剩一元钱,请问这个人原先口袋有多少钱.

Answer 1

设那个人钱为x,1／2x+1 是第一个的钱.x-(1/2x+1) 是口袋里还剩的钱.给第二个乞丐
1／2(x-(1/2x+1))+2 (1／2 剩下的钱＋2) 然后还剩下 x－(1/2x+1)-1/2(x-(1/2x+1)) （x减第一次减第二次）第三次就难了,是 1／2(x-(1/2x+1)-1/2(x-(1/2x+1)))+3 注意大括号里的是第二次剩下的钱.然后就可以列出方程了：）
x-(1／2(x-(1/2x+1)-1/2(x-(1/2x+1)))+3)- (x－(1/2x+1)-1/2(x-(1/2x+1)))-(x-(1/2x+1)))=1
太累了就不解释了自己慢慢想吧!
1／2(x-(1/2x+1)-1/2(x-(1/2x+1)))+3)- (x－(1/2x+1)-1/2(x-(1/2x+1)))-(x-(1/2x+1))＝1＋x
x-(1/2x+1)-1/2(x-(1/2x+1)))+3)- (x－(1/2x+1)-1/2(x-(1/2x+1)))-(x-(1/2x+1)=2+2x
(1/2x+1)-1/2(x-(1/2x+1)+3)- (x－(1/2x+1)-1/2(x-(1/2x+1)-(x-(1/2x+1)=2+3x
好吧现在开始破括号
(1/2x+1)-1/2x-1/2(1/2x+1)+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))=2+3x
然后我就比较笨的开始了,本人代数不怎么样.
1/2x+1=2+3x+1/2x-1/2(1/2x+1)+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
0.5x+1=2+3.5x-1/2(1/2x+1)+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
2+3.5x-1/2(1/2x+1)+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))=0.5x+1
0.5x+1=2+3.5x-0.25x+0.5+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
已经比以前简单多了!：）
0.5x+1=2.5+3.25x+1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
0.5x+1-2.5+3.25x=1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
0.5x-1.5+3.25x=1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
3.75x-1.5=1.5-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
3.75x=-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))
-(x-1/2x+1)-1/2x-1/2(1/2x+1)-(x-(1/2x+1))=3.75x
-x+1/2x-1-1/2x-0.25x-0.5-x+1/2x+1=3.75x
太好了没有括号了!：D
1/2x-1-1/2x-0.25x-0.5-x+1/2x+1=3.75x
-1-0.25x-0.5-x+0.5x+1=3.75x
0-0.25x-0.5-x+0.5x=3.75x
0-0.25x=3.75x
0=4x
x=0?!
好吧烦死我了代数一直不是我的强项这是谁出的坑爹问题谁解出来祝贺谁.真心祝愿那三个乞丐能活下来谁给个钱都要算半天的!
也希望您看在我给你做了一个小时的份上选我为最佳答案!