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计算(1)-3+4+7-5(2)−24÷(−32)+6×(−13)(3)(34−76+1112)×(−36)(4)−14−[1−(1−0.5×13)]×6.
题目详情
计算
(1)-3+4+7-5
(2)−24÷(−
)+6×(−
)
(3)(
−
+
)×(−36)
(4)−14−[1−(1−0.5×
)]×6.
(1)-3+4+7-5
(2)−24÷(−
3 |
2 |
1 |
3 |
(3)(
3 |
4 |
7 |
6 |
11 |
12 |
(4)−14−[1−(1−0.5×
1 |
3 |
▼优质解答
答案和解析
(1)-3+4+7-5,
=-8+11,
=3;
(2)-24÷(-
)+6×(-
),
=24×
-2,
=16-2,
=14;
(3)(
-
+
)×(-36),
=
×(-36)-
×(-36)+
×(-36),
=-27+42-33,
=-60+42,
=-18;
(4)-14-[1-(1-0.5×
)]×6,
=-1-[1-(1-
)]×6,
=-1-(1-
)×6,
=-1-
×6,
=-1-1,
=-2.
=-8+11,
=3;
(2)-24÷(-
3 |
2 |
1 |
3 |
=24×
2 |
3 |
=16-2,
=14;
(3)(
3 |
4 |
7 |
6 |
11 |
12 |
=
3 |
4 |
7 |
6 |
11 |
12 |
=-27+42-33,
=-60+42,
=-18;
(4)-14-[1-(1-0.5×
1 |
3 |
=-1-[1-(1-
1 |
6 |
=-1-(1-
5 |
6 |
=-1-
1 |
6 |
=-1-1,
=-2.
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