早教吧作业答案频道 -->其他-->
能用简便方法的用简便方法计算.105×32-3232÷32125×313×0.8×310(17−19)×63−23210.5×[(6.05-3.35)÷1.5](56−34)×25÷120.75×16+34×5−75%.
题目详情
能用简便方法的用简便方法计算.
105×32-3232÷32
125×3
×0.8×
(
−
)× 63−
210.5×[(6.05-3.35)÷1.5]
(
−
)×
÷
0.75×16+
×5−75%.
105×32-3232÷32
125×3
1 |
3 |
3 |
10 |
(
1 |
7 |
1 |
9 |
2 |
3 |
210.5×[(6.05-3.35)÷1.5]
(
5 |
6 |
3 |
4 |
2 |
5 |
1 |
2 |
0.75×16+
3 |
4 |
▼优质解答
答案和解析
(1)105×32-3232÷32,
=3360-101,
=3159;
(2)125×3
×0.8×
,
=125×0.8×(
×
),
=100×1,
=100;
(3)(
-
)×63-
,
=
×63-
×63-
,
=9-7-
,
=2-
,
=1
;
(4)210.5×[(6.05-3.35)÷1.5],
=210.5×[(6.05-3.35)÷1.5],
=210.5×[2.7÷1.5],
=210.5×1.8,
=378.9;
(5)(
-
)×
÷
,
=(
-
)×
×2,
=
×
×2,
=
;
(6)0.75×16+
×5−75%,
=0.75×16+0.75×5-0.75,
=(16+5-1)×0.75,
=20×0.75,
=15.
=3360-101,
=3159;
(2)125×3
1 |
3 |
3 |
10 |
=125×0.8×(
10 |
3 |
3 |
10 |
=100×1,
=100;
(3)(
1 |
7 |
1 |
9 |
2 |
3 |
=
1 |
7 |
1 |
9 |
2 |
3 |
=9-7-
2 |
3 |
=2-
2 |
3 |
=1
1 |
3 |
(4)210.5×[(6.05-3.35)÷1.5],
=210.5×[(6.05-3.35)÷1.5],
=210.5×[2.7÷1.5],
=210.5×1.8,
=378.9;
(5)(
5 |
6 |
3 |
4 |
2 |
5 |
1 |
2 |
=(
10 |
12 |
9 |
12 |
2 |
5 |
=
1 |
12 |
2 |
5 |
=
1 |
15 |
(6)0.75×16+
3 |
4 |
=0.75×16+0.75×5-0.75,
=(16+5-1)×0.75,
=20×0.75,
=15.
看了 能用简便方法的用简便方法计算...的网友还看了以下:
简便计算1.(+1)+(-3)+(+5)+(-7)+…+(+97)+(-99)2.1/2+1/3+ 2020-04-07 …
1/1,-1/2,-2/1,1/3,2/2,1/3,-1/4,-2/3,-3/2,-4/1,1/5 2020-04-09 …
、按一定规律排列的一串数:1/1,-1/3,2/3,-3/3,1/5,-2/5,3/5,-4/5, 2020-05-14 …
谁会用MATLAB计算 权向量矩阵是A=[1,1/2,3,1,6,8,9,1/2 2,1,5,2, 2020-05-15 …
数学分数简便计算,11/24*16 1/4*2/7 6/12*6+5/12*6 3/5*5/6 5 2020-05-16 …
1.已知非空集合P满足(1)P包含于{1,2,3,4,5}(2)a∈P,则6-a∈P.那么,符合上 2020-05-21 …
高数极限的问题刚才搜了一个题目X趋向无穷大lim[((2+x)^1.5-x^1.5)/[(x)^( 2020-06-27 …
(1)-22-(-1)3(2)4-5*(-1/2)3(3)(-10)2/5×(-2/5)(4)(- 2020-07-22 …
序列:1/1,1/2,2/2,1/3,2/3,3/3,1/4,2/4,3/4,4/4,1/5,2/5 2020-12-05 …
计算.4÷8/3-1/2=1/5+2/7÷5/7=8÷2/3+4=25÷(1-1/6)=18÷(1+ 2020-12-26 …